3(4/5)x^2+6x-5=0

Lösung

3 (\frac{4}{5}) x^{2} + 6 x - 5 = 0

x = \frac{5 ( 21 - 3 )}{12}, x = - \frac{5 ( 3 + 21 )}{12}

Dezimale

x = 0.65940 \dots, x = - 3.15940 \dots

Schritte zur Lösung

3 (\frac{4}{5}) x^{2} + 6 x - 5 = 0

Schreibe

3 (\frac{4}{5}) x^{2} + 6 x - 5

um:

\frac{12}{5} x^{2} + 6 x - 5

\frac{12}{5} x^{2} + 6 x - 5 = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

\frac{12 x ^{2}}{5} + 6 x - 5 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot \frac{12}{5} ( - 5 )}{2 \cdot \frac{12}{5}}

6^{2} - 4 \cdot \frac{12}{5} (- 5) = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot \frac{12}{5}}

Trenne die Lösungen

x_{1} = \frac{- 6 + 2 21}{2 \cdot \frac{12}{5}}, x_{2} = \frac{- 6 - 2 21}{2 \cdot \frac{12}{5}}

x = \frac{- 6 + 2 21}{2 \frac{12}{5}} : \frac{5 ( 21 - 3 )}{12}

x = \frac{- 6 - 2 21}{2 \frac{12}{5}} : - \frac{5 ( 3 + 21 )}{12}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{5 ( 21 - 3 )}{12}, x = - \frac{5 ( 3 + 21 )}{12}

x^{2} + 2 x + c = 0

x^{2} + 4 x - 22 = 0

x^{2} - 12 x - 1725 = 0

2 x^{2} + 5 x = - 4

2 x^{2} + 5 x = - 2