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人気のある代数 >

(ax^2+3bx+8)+(2x^2-4x+c)=5x^2-2x+3

解

(a x^{2} + 3 b x + 8) + (2 x^{2} - 4 x + c) = 5 x^{2} - 2 x + 3

解

x = \frac{- 3 b + 2 + - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}, x = \frac{- 3 b + 2 - - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}; a \neq = 3

解答ステップ

(a x^{2} + 3 b x + 8) + (2 x^{2} - 4 x + c) = 5 x^{2} - 2 x + 3

改良

a x^{2} + 3 b x + 8 + 2 x^{2} - 4 x + c = 5 x^{2} - 2 x + 3

3

を左側に移動します

a x^{2} + 2 x^{2} + 3 b x - 4 x + c + 5 = 5 x^{2} - 2 x

2 x

を左側に移動します

a x^{2} + 2 x^{2} + 3 b x - 2 x + c + 5 = 5 x^{2}

5 x^{2}

を左側に移動します

a x^{2} - 3 x^{2} + 3 b x - 2 x + c + 5 = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(a - 3) x^{2} + (3 b - 2) x + c + 5 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 3 b - 2 ) \pm ( 3 b - 2 ) ^{2} - 4 ( a - 3 ) ( c + 5 )}{2 ( a - 3 )}

簡素化

(3 b - 2)^{2} - 4 (a - 3) (c + 5) : - 4 a c - 20 a + 9 b^{2} + 12 c + 64 - 12 b

x_{1, 2} = \frac{- ( 3 b - 2 ) \pm - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}; a \neq = 3

解を分離する

x_{1} = \frac{- ( 3 b - 2 ) + - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}, x_{2} = \frac{- ( 3 b - 2 ) - - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}

x = \frac{- ( 3 b - 2 ) + - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )} : \frac{- 3 b + 2 + - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}

x = \frac{- ( 3 b - 2 ) - - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )} : \frac{- 3 b + 2 - - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}

二次equationの解:

x = \frac{- 3 b + 2 + - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}, x = \frac{- 3 b + 2 - - 4 a c - 20 a + 9 b ^{2} + 12 c + 64 - 12 b}{2 ( a - 3 )}; a \neq = 3

グラフ

人気の例

completesquare n^2-24n

co m pl e t es q u a re n^{2} - 24 n

x^{2} - 7 x = - 1

y^{2} - 5 y - 84 = 0

(x^2)/2-(7x)/(20)= 3/10

\frac{x ^{2}}{2} - \frac{7 x}{20} = \frac{3}{10}

x^{2} = - 0.01