What are the solutions to the equation x^2+2.5x+1=0 ?

The solutions to the equation x^2+2.5x+1=0 are x=-1/2 ,x=-2

Find the zeros of x^2+2.5x+1=0

The zeros of x^2+2.5x+1=0 are x=-1/2 ,x=-2

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x^{2} + 2.5 x + 1 = 0

x = - \frac{1}{2}, x = - 2

Decimal Notation

x = - 0.5, x = - 2

Solution steps

x^{2} + 2.5 x + 1 = 0

Multiply both sides by

10

10 x^{2} + 25 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

2 5^{2} - 4 \cdot 10 \cdot 10 = 15

x_{1, 2} = \frac{- 25 \pm 15}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 25 + 15}{2 \cdot 10}, x_{2} = \frac{- 25 - 15}{2 \cdot 10}

x = \frac{- 25 + 15}{2 \cdot 10} : - \frac{1}{2}

x = \frac{- 25 - 15}{2 \cdot 10} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 2

(x + 2)^{2} - 2 = 0

2 r^{2} + 60 r + 400 = 0

10 x^{2} + 48 = 0

a^{2} - 25 = 0

6 t^{2} + 6 t - 12 = 0

What are the solutions to the equation x^2+2.5x+1=0 ?
The solutions to the equation x^2+2.5x+1=0 are x=-1/2 ,x=-2
Find the zeros of x^2+2.5x+1=0
The zeros of x^2+2.5x+1=0 are x=-1/2 ,x=-2