v^2+10v+24=0

解

v^{2} + 10 v + 24 = 0

v = - 4, v = - 6

解答ステップ

v^{2} + 10 v + 24 = 0

解くとthe二次式

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

v_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

解を分離する

v_{1} = \frac{- 10 + 2}{2 \cdot 1}, v_{2} = \frac{- 10 - 2}{2 \cdot 1}

v = \frac{- 10 + 2}{2 \cdot 1} : - 4

v = \frac{- 10 - 2}{2 \cdot 1} : - 6

二次equationの解:

v = - 4, v = - 6