What are the solutions to the equation p^2+3p=2 ?

The solutions to the equation p^2+3p=2 are p=(-3+sqrt(17))/2 ,p=(-3-sqrt(17))/2

Find the zeros of p^2+3p=2

The zeros of p^2+3p=2 are p=(-3+sqrt(17))/2 ,p=(-3-sqrt(17))/2

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p^{2} + 3 p = 2

p = \frac{- 3 + 17}{2}, p = \frac{- 3 - 17}{2}

Decimal Notation

p = 0.56155 \dots, p = - 3.56155 \dots

Solution steps

p^{2} + 3 p = 2

Move

2

to the left side

p^{2} + 3 p - 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

p_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 3 + 17}{2 \cdot 1}, p_{2} = \frac{- 3 - 17}{2 \cdot 1}

p = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

p = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

p = \frac{- 3 + 17}{2}, p = \frac{- 3 - 17}{2}

9 x^{2} + 18 x = 0

x^{2} + 16 = 81

- 3 x^{2} + 2 x - 5 = 0

5 X^{2} - 500 = 0

3 x^{2} + 32 x = 11

What are the solutions to the equation p^2+3p=2 ?
The solutions to the equation p^2+3p=2 are p=(-3+sqrt(17))/2 ,p=(-3-sqrt(17))/2
Find the zeros of p^2+3p=2
The zeros of p^2+3p=2 are p=(-3+sqrt(17))/2 ,p=(-3-sqrt(17))/2