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受欢迎的代数 >

(x^2+4)15=(x-3)(x-5)4

解答

(x^{2} + 4) \cdot 15 = (x - 3) (x - 5) \cdot 4

解答

x = - \frac{32}{11}, x = 0

+1

十进制

x = - 2.90909 \dots, x = 0

求解步骤

(x^{2} + 4) \cdot 15 = (x - 3) (x - 5) \cdot 4

展开

(x^{2} + 4) \cdot 15 : 15 x^{2} + 60

展开

(x - 3) (x - 5) \cdot 4 : 4 x^{2} - 32 x + 60

15 x^{2} + 60 = 4 x^{2} - 32 x + 60

交换两边

4 x^{2} - 32 x + 60 = 15 x^{2} + 60

将

60

para o lado esquerdo

4 x^{2} - 32 x = 15 x^{2}

将

15 x^{2}

para o lado esquerdo

- 11 x^{2} - 32 x = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 ( - 11 ) \cdot 0}{2 ( - 11 )}

(- 32)^{2} - 4 (- 11) \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 ( - 11 )}

将解分隔开

x_{1} = \frac{- ( - 32 ) + 32}{2 ( - 11 )}, x_{2} = \frac{- ( - 32 ) - 32}{2 ( - 11 )}

x = \frac{- ( - 32 ) + 32}{2 ( - 11 )} : - \frac{32}{11}

x = \frac{- ( - 32 ) - 32}{2 ( - 11 )} : 0

二次方程组的解是:

x = - \frac{32}{11}, x = 0

作图

流行的例子

121 - a^{2} = 0

4 - x^{2} = 4 - x

(x - 8)^{2} = - 16 x

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8 x - 65 + x^{2} = 0