-x^2+6x-9=0

解答

- x^{2} + 6 x - 9 = 0

x = 3

求解步骤

- x^{2} + 6 x - 9 = 0

使用求根公式求解

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 9) = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 ( - 1 )}

x = \frac{- 6}{2 ( - 1 )}

\frac{- 6}{2 ( - 1 )} = 3

x = 3

二次方程组的解是:

x = 3

f a c t or 6 c^{2} + 2 c^{4} - c

f a c t or x^{3} + 12 x^{2} + 27 x - 40

\frac{1}{4} x = 5

s im pl i f y \frac{2 π}{\frac{2}{5}}

16 x - 6 = 26