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人気のある代数 >

x^2-(a+d)x+(ad-bc)=0

解

x^{2} - (a + d) x + (a d - b c) = 0

解

x = \frac{a + d + a ^{2} - 2 a d + d ^{2} + 4 b c}{2}, x = \frac{a + d - a ^{2} - 2 a d + d ^{2} + 4 b c}{2}

解答ステップ

x^{2} - (a + d) x + (a d - b c) = 0

拡張

x^{2} - (a + d) x + (a d - b c) : x^{2} - a x - d x + a d - b c

x^{2} - a x - d x + a d - b c = 0

標準的な形式で書く

a x^{2} + b x + c = 0

x^{2} - (a + d) x + a d - b c = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - a - d ) \pm ( - a - d ) ^{2} - 4 \cdot 1 \cdot ( a d - b c )}{2 \cdot 1}

簡素化

(- a - d)^{2} - 4 \cdot 1 \cdot (a d - b c) : a^{2} - 2 a d + d^{2} + 4 b c

x_{1, 2} = \frac{- ( - a - d ) \pm a ^{2} - 2 a d + d ^{2} + 4 b c}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - a - d ) + a ^{2} - 2 a d + d ^{2} + 4 b c}{2 \cdot 1}, x_{2} = \frac{- ( - a - d ) - a ^{2} - 2 a d + d ^{2} + 4 b c}{2 \cdot 1}

x = \frac{- ( - a - d ) + a ^{2} - 2 a d + d ^{2} + 4 b c}{2 \cdot 1} : \frac{a + d + a ^{2} - 2 a d + d ^{2} + 4 b c}{2}

x = \frac{- ( - a - d ) - a ^{2} - 2 a d + d ^{2} + 4 b c}{2 \cdot 1} : \frac{a + d - a ^{2} - 2 a d + d ^{2} + 4 b c}{2}

二次equationの解:

x = \frac{a + d + a ^{2} - 2 a d + d ^{2} + 4 b c}{2}, x = \frac{a + d - a ^{2} - 2 a d + d ^{2} + 4 b c}{2}

グラフ

人気の例

9 x^{2} - 5 x = 0

solvefor x,x^2-y^2+z^2=1

so l v e f or x, x^{2} - y^{2} + z^{2} = 1

10 r^{2} - 2 r - 19 = 0

a^{2} + 7^{2} = 9^{2}

16 x^{2} = 64