q^2+40q=0

解

q^{2} + 40 q = 0

q = 0, q = - 40

解答ステップ

q^{2} + 40 q = 0

解くとthe二次式

q_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 0 = 40

q_{1, 2} = \frac{- 40 \pm 40}{2 \cdot 1}

解を分離する

q_{1} = \frac{- 40 + 40}{2 \cdot 1}, q_{2} = \frac{- 40 - 40}{2 \cdot 1}

q = \frac{- 40 + 40}{2 \cdot 1} : 0

q = \frac{- 40 - 40}{2 \cdot 1} : - 40

二次equationの解:

q = 0, q = - 40