What are the solutions to the equation 3z^2-4z+5=0 ?

The solutions to the equation 3z^2-4z+5=0 are z= 2/3+i(sqrt(11))/3 ,z= 2/3-i(sqrt(11))/3

Find the zeros of 3z^2-4z+5=0

The zeros of 3z^2-4z+5=0 are z= 2/3+i(sqrt(11))/3 ,z= 2/3-i(sqrt(11))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 z^{2} - 4 z + 5 = 0

z = \frac{2}{3} + i \frac{11}{3}, z = \frac{2}{3} - i \frac{11}{3}

Solution steps

3 z^{2} - 4 z + 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 5 : 211 i

z_{1, 2} = \frac{- ( - 4 ) \pm 2 11 i}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3}, z_{2} = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3}

z = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3} : \frac{2}{3} + i \frac{11}{3}

z = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3} : \frac{2}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

z = \frac{2}{3} + i \frac{11}{3}, z = \frac{2}{3} - i \frac{11}{3}

(x + 4) (x + 3) = 0

- x^{2} + x + \frac{11}{6} = 0

a, \int (x) d x = a^{2}

4 X^{2} = - 8

(3 x - 2) (7 x - 4) = 0

What are the solutions to the equation 3z^2-4z+5=0 ?
The solutions to the equation 3z^2-4z+5=0 are z= 2/3+i(sqrt(11))/3 ,z= 2/3-i(sqrt(11))/3
Find the zeros of 3z^2-4z+5=0
The zeros of 3z^2-4z+5=0 are z= 2/3+i(sqrt(11))/3 ,z= 2/3-i(sqrt(11))/3