x^2+42x=0

解

x^{2} + 42 x = 0

x = 0, x = - 42

解答ステップ

x^{2} + 42 x = 0

解くとthe二次式

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4 2^{2} - 4 \cdot 1 \cdot 0 = 42

x_{1, 2} = \frac{- 42 \pm 42}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 42 + 42}{2 \cdot 1}, x_{2} = \frac{- 42 - 42}{2 \cdot 1}

x = \frac{- 42 + 42}{2 \cdot 1} : 0

x = \frac{- 42 - 42}{2 \cdot 1} : - 42

二次equationの解:

x = 0, x = - 42