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人気のある代数 >

-4.9t^2+12t+15=0

解

- 4.9 t^{2} + 12 t + 15 = 0

解

t = - \frac{5 ( 438 - 12 )}{49}, t = \frac{5 ( 12 + 438 )}{49}

+1

十進法表記

t = - 0.91106 \dots, t = 3.36004 \dots

解答ステップ

- 4.9 t^{2} + 12 t + 15 = 0

以下で両辺を乗じる:

10

- 49 t^{2} + 120 t + 150 = 0

解くとthe二次式

t_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 ( - 49 ) \cdot 150}{2 ( - 49 )}

12 0^{2} - 4 (- 49) \cdot 150 = 10438

t_{1, 2} = \frac{- 120 \pm 10 438}{2 ( - 49 )}

解を分離する

t_{1} = \frac{- 120 + 10 438}{2 ( - 49 )}, t_{2} = \frac{- 120 - 10 438}{2 ( - 49 )}

t = \frac{- 120 + 10 438}{2 ( - 49 )} : - \frac{5 ( 438 - 12 )}{49}

t = \frac{- 120 - 10 438}{2 ( - 49 )} : \frac{5 ( 12 + 438 )}{49}

二次equationの解:

t = - \frac{5 ( 438 - 12 )}{49}, t = \frac{5 ( 12 + 438 )}{49}

グラフ

人気の例

1 = (1 - y) (2 - y)

3 x^{2} + 5 = 32

4 b^{2} + 2 b - 2 = 0

10 x^{2} - 12 x = 0

x^{2} - 65 x + 950 = 0