What are the solutions to the equation solvefor x,20m^2=(2x+6m)x ?

The solutions to the equation solvefor x,20m^2=(2x+6m)x are x=2m,x=-5m

Find the zeros of solvefor x,20m^2=(2x+6m)x

The zeros of solvefor x,20m^2=(2x+6m)x are x=2m,x=-5m

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solve for

x, 20 m^{2} = (2 x + 6 m) x

x = 2 m, x = - 5 m

Solution steps

20 m^{2} = (2 x + 6 m) x

Expand

(2 x + 6 m) x : 2 x^{2} + 6 x m

20 m^{2} = 2 x^{2} + 6 x m

Switch sides

2 x^{2} + 6 x m = 20 m^{2}

Move

20 m^{2}

to the left side

2 x^{2} + 6 x m - 20 m^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 6 m x - 20 m^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 m \pm ( 6 m ) ^{2} - 4 \cdot 2 ( - 20 m ^{2} )}{2 \cdot 2}

Simplify

(6 m)^{2} - 4 \cdot 2 (- 20 m^{2}) : 14 m

x_{1, 2} = \frac{- 6 m \pm 14 m}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 m + 14 m}{2 \cdot 2}, x_{2} = \frac{- 6 m - 14 m}{2 \cdot 2}

x = \frac{- 6 m + 14 m}{2 \cdot 2} : 2 m

x = \frac{- 6 m - 14 m}{2 \cdot 2} : - 5 m

The solutions to the quadratic equation are:

x = 2 m, x = - 5 m

2 x^{2} = 75 - 5 x

\frac{1}{4} x^{2} = 0

- 3 x^{2} + 2 x + 1

4.9 x^{2} - 10 x = 0

U, A = 18 X^{2} - 27 X U^{2}

What are the solutions to the equation solvefor x,20m^2=(2x+6m)x ?
The solutions to the equation solvefor x,20m^2=(2x+6m)x are x=2m,x=-5m
Find the zeros of solvefor x,20m^2=(2x+6m)x
The zeros of solvefor x,20m^2=(2x+6m)x are x=2m,x=-5m