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受欢迎的代数 >

(14-b)^3+b^3=812

解答

(14 - b)^{3} + b^{3} = 812

解答

b = 7 + 3, b = 7 - 3

+1

十进制

b = 8.73205 \dots, b = 5.26794 \dots

求解步骤

(14 - b)^{3} + b^{3} = 812

展开

(14 - b)^{3} + b^{3} : 2744 - 588 b + 42 b^{2}

2744 - 588 b + 42 b^{2} = 812

将

812

para o lado esquerdo

42 b^{2} - 588 b + 1932 = 0

使用求根公式求解

b_{1, 2} = \frac{- ( - 588 ) \pm ( - 588 ) ^{2} - 4 \cdot 42 \cdot 1932}{2 \cdot 42}

(- 588)^{2} - 4 \cdot 42 \cdot 1932 = 843

b_{1, 2} = \frac{- ( - 588 ) \pm 84 3}{2 \cdot 42}

将解分隔开

b_{1} = \frac{- ( - 588 ) + 84 3}{2 \cdot 42}, b_{2} = \frac{- ( - 588 ) - 84 3}{2 \cdot 42}

b = \frac{- ( - 588 ) + 84 3}{2 \cdot 42} : 7 + 3

b = \frac{- ( - 588 ) - 84 3}{2 \cdot 42} : 7 - 3

二次方程组的解是:

b = 7 + 3, b = 7 - 3

作图

流行的例子

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