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受欢迎的代数 >

1x+4-x^2-x=x+10x^2+2x-8

解答

1 x + 4 - x^{2} - x = x + 10 x^{2} + 2 x - 8

解答

x = \frac{- 3 + 537}{22}, x = \frac{- 3 - 537}{22}

+1

十进制

x = 0.91696 \dots, x = - 1.18969 \dots

求解步骤

1 \cdot x + 4 - x^{2} - x = x + 10 x^{2} + 2 x - 8

整理后得

- x^{2} + 4 = 10 x^{2} + 3 x - 8

交换两边

10 x^{2} + 3 x - 8 = - x^{2} + 4

将

4

para o lado esquerdo

10 x^{2} + 3 x - 12 = - x^{2}

将

x^{2}

para o lado esquerdo

11 x^{2} + 3 x - 12 = 0

使用求根公式求解

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 11 ( - 12 )}{2 \cdot 11}

3^{2} - 4 \cdot 11 (- 12) = 537

x_{1, 2} = \frac{- 3 \pm 537}{2 \cdot 11}

将解分隔开

x_{1} = \frac{- 3 + 537}{2 \cdot 11}, x_{2} = \frac{- 3 - 537}{2 \cdot 11}

x = \frac{- 3 + 537}{2 \cdot 11} : \frac{- 3 + 537}{22}

x = \frac{- 3 - 537}{2 \cdot 11} : \frac{- 3 - 537}{22}

二次方程组的解是:

x = \frac{- 3 + 537}{22}, x = \frac{- 3 - 537}{22}

作图

流行的例子

solvefor b,M=a+(b^2)/c

so l v e f or b, M = a + \frac{b ^{2}}{c}

4 - x^{2} = 4 - 2 x

a = 3.14 r^{2}

p^{2} - 14 p + 49 = 0

- 3 x^{2} - 7 x + 10 = 0