8x^2+18x-24=0

解答

8 x^{2} + 18 x - 24 = 0

x = \frac{- 9 + 273}{8}, x = - \frac{9 + 273}{8}

十进制

x = 0.94033 \dots, x = - 3.19033 \dots

求解步骤

8 x^{2} + 18 x - 24 = 0

使用求根公式求解

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 8 ( - 24 )}{2 \cdot 8}

1 8^{2} - 4 \cdot 8 (- 24) = 2273

x_{1, 2} = \frac{- 18 \pm 2 273}{2 \cdot 8}

将解分隔开

x_{1} = \frac{- 18 + 2 273}{2 \cdot 8}, x_{2} = \frac{- 18 - 2 273}{2 \cdot 8}

x = \frac{- 18 + 2 273}{2 \cdot 8} : \frac{- 9 + 273}{8}

x = \frac{- 18 - 2 273}{2 \cdot 8} : - \frac{9 + 273}{8}

二次方程组的解是:

x = \frac{- 9 + 273}{8}, x = - \frac{9 + 273}{8}

6 r^{2} - 7 r + 2 = 0

8 (6 - x) - 3 x (6 - x) = 0

co m pl e t es q u a re x^{2} + 2 x - 7 = 0

so l v e f or y, x^{2} y^{2} - 3 x + y = 4

- 4 x^{2} - 4 x + 5 = - 7 x^{2}