(m-3)x^2-2mx+m+2=0

解

(m - 3) x^{2} - 2 m x + m + 2 = 0

x = \frac{m + m + 6}{m - 3}, x = \frac{m - m + 6}{m - 3}; m \neq = 3

解答ステップ

(m - 3) x^{2} - 2 m x + m + 2 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 2 m ) \pm ( - 2 m ) ^{2} - 4 ( m - 3 ) ( m + 2 )}{2 ( m - 3 )}

簡素化

(- 2 m)^{2} - 4 (m - 3) (m + 2) : 2 m + 6

x_{1, 2} = \frac{- ( - 2 m ) \pm 2 m + 6}{2 ( m - 3 )}; m \neq = 3

解を分離する

x_{1} = \frac{- ( - 2 m ) + 2 m + 6}{2 ( m - 3 )}, x_{2} = \frac{- ( - 2 m ) - 2 m + 6}{2 ( m - 3 )}

x = \frac{- ( - 2 m ) + 2 m + 6}{2 ( m - 3 )} : \frac{m + m + 6}{m - 3}

x = \frac{- ( - 2 m ) - 2 m + 6}{2 ( m - 3 )} : \frac{m - m + 6}{m - 3}

二次equationの解:

x = \frac{m + m + 6}{m - 3}, x = \frac{m - m + 6}{m - 3}; m \neq = 3