h^2-16h-17=0

解

h^{2} - 16 h - 17 = 0

h = 17, h = - 1

解答ステップ

h^{2} - 16 h - 17 = 0

解くとthe二次式

h_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 17) = 18

h_{1, 2} = \frac{- ( - 16 ) \pm 18}{2 \cdot 1}

解を分離する

h_{1} = \frac{- ( - 16 ) + 18}{2 \cdot 1}, h_{2} = \frac{- ( - 16 ) - 18}{2 \cdot 1}

h = \frac{- ( - 16 ) + 18}{2 \cdot 1} : 17

h = \frac{- ( - 16 ) - 18}{2 \cdot 1} : - 1

二次equationの解:

h = 17, h = - 1