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受欢迎的代数 >

-3t^2+4t+40=-t+15

解答

- 3 t^{2} + 4 t + 40 = - t + 15

解答

t = - \frac{- 5 + 5 13}{6}, t = \frac{5 + 5 13}{6}

+1

十进制

t = - 2.17129 \dots, t = 3.83795 \dots

求解步骤

- 3 t^{2} + 4 t + 40 = - t + 15

将

15

para o lado esquerdo

- 3 t^{2} + 4 t + 25 = - t

将

t

para o lado esquerdo

- 3 t^{2} + 5 t + 25 = 0

使用求根公式求解

t_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) \cdot 25}{2 ( - 3 )}

5^{2} - 4 (- 3) \cdot 25 = 513

t_{1, 2} = \frac{- 5 \pm 5 13}{2 ( - 3 )}

将解分隔开

t_{1} = \frac{- 5 + 5 13}{2 ( - 3 )}, t_{2} = \frac{- 5 - 5 13}{2 ( - 3 )}

t = \frac{- 5 + 5 13}{2 ( - 3 )} : - \frac{- 5 + 5 13}{6}

t = \frac{- 5 - 5 13}{2 ( - 3 )} : \frac{5 + 5 13}{6}

二次方程组的解是:

t = - \frac{- 5 + 5 13}{6}, t = \frac{5 + 5 13}{6}

作图

流行的例子

a^2+((5sqrt(3))/2+a)^2=5^2

a^{2} + (\frac{5 3}{2} + a)^{2} = 5^{2}

5n^2+9.8n-1200=0

5 n^{2} + 9.8 n - 1200 = 0

x^{2} - 3 x - 26 = 2

solvefor x,y^3+3x^2y=c_{1}

so l v e f or x, y^{3} + 3 x^{2} y = c_{1}

8 x^{2} + 7 x - 1666 = 0