What are the solutions to the equation completesquare x^2-12x+7=0 ?

The solutions to the equation completesquare x^2-12x+7=0 are x=sqrt(29)+6,x=-sqrt(29)+6

Find the zeros of completesquare x^2-12x+7=0

The zeros of completesquare x^2-12x+7=0 are x=sqrt(29)+6,x=-sqrt(29)+6

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x^{2} - 12 x + 7 = 0

x = 29 + 6, x = - 29 + 6

Decimal Notation

x = 11.38516 \dots, x = 0.61483 \dots

Solution steps

x^{2} - 12 x + 7 = 0

Move

7

to the right side

x^{2} - 12 x = - 7

Rewrite in the form

(x + a)^{2} = b

(x - 6)^{2} = 29

For

the solutions are

f (x) = a, - a

Solve

x - 6 = 29 : x = 29 + 6

Solve

x - 6 = - 29 : x = - 29 + 6

The solutions to the quadratic equation are:

x = 29 + 6, x = - 29 + 6

4 r^{3} s + 864 s^{4} = 4 s (r + 6 s)

(x - 14)^{2} + 13 = 12

ab x^{2} = (a - b)^{2} (x + 1)

- 6 x^{2} - 586 = 84 x - 484 x - 4

15 x^{2} + 6 = 2 x

What are the solutions to the equation completesquare x^2-12x+7=0 ?
The solutions to the equation completesquare x^2-12x+7=0 are x=sqrt(29)+6,x=-sqrt(29)+6
Find the zeros of completesquare x^2-12x+7=0
The zeros of completesquare x^2-12x+7=0 are x=sqrt(29)+6,x=-sqrt(29)+6