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受欢迎的代数 >

quadraticformula 2p^2+8p+(k+1)=0

解答

2 p^{2} + 8 p + (k + 1) = 0

解答

p = \frac{- 8 + - 8 k + 56}{4}, p = \frac{- 8 - - 8 k + 56}{4}

求解步骤

2 p^{2} + 8 p + (k + 1) = 0

整理后得

2 p^{2} + 8 p + k + 1 = 0

使用求根公式求解

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( k + 1 )}{2 \cdot 2}

化简

8^{2} - 4 \cdot 2 (k + 1) : - 8 k + 56

p_{1, 2} = \frac{- 8 \pm - 8 k + 56}{2 \cdot 2}

将解分隔开

p_{1} = \frac{- 8 + - 8 k + 56}{2 \cdot 2}, p_{2} = \frac{- 8 - - 8 k + 56}{2 \cdot 2}

p = \frac{- 8 + - 8 k + 56}{2 \cdot 2} : \frac{- 8 + - 8 k + 56}{4}

p = \frac{- 8 - - 8 k + 56}{2 \cdot 2} : \frac{- 8 - - 8 k + 56}{4}

二次方程组的解是:

p = \frac{- 8 + - 8 k + 56}{4}, p = \frac{- 8 - - 8 k + 56}{4}

作图

流行的例子

3 x^{2} - 11 x - 42 = 0

n^{2} + 2 n - 120 = 0

3 x^{2} - 8 x + 16 = 0

x^{2} + 8 x + 4 = - 3

x^{2} + 10 x + 32 = 11