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受欢迎的代数 >

12k(2k+11)=12(2k+12)

解答

12 k (2 k + 11) = 12 (2 k + 12)

解答

k = \frac{- 9 + 177}{4}, k = - \frac{9 + 177}{4}

+1

十进制

k = 1.07603 \dots, k = - 5.57603 \dots

求解步骤

12 k (2 k + 11) = 12 (2 k + 12)

展开

12 k (2 k + 11) : 24 k^{2} + 132 k

展开

12 (2 k + 12) : 24 k + 144

24 k^{2} + 132 k = 24 k + 144

将

144

para o lado esquerdo

24 k^{2} + 132 k - 144 = 24 k

将

24 k

para o lado esquerdo

24 k^{2} + 108 k - 144 = 0

使用求根公式求解

k_{1, 2} = \frac{- 108 \pm 10 8 ^{2} - 4 \cdot 24 ( - 144 )}{2 \cdot 24}

10 8^{2} - 4 \cdot 24 (- 144) = 12177

k_{1, 2} = \frac{- 108 \pm 12 177}{2 \cdot 24}

将解分隔开

k_{1} = \frac{- 108 + 12 177}{2 \cdot 24}, k_{2} = \frac{- 108 - 12 177}{2 \cdot 24}

k = \frac{- 108 + 12 177}{2 \cdot 24} : \frac{- 9 + 177}{4}

k = \frac{- 108 - 12 177}{2 \cdot 24} : - \frac{9 + 177}{4}

二次方程组的解是:

k = \frac{- 9 + 177}{4}, k = - \frac{9 + 177}{4}

作图

流行的例子

- x^{2} - x - 8 = 0

2 x^{2} - 11 x = - 12

17^2=w^2+(3w+9)^2

1 7^{2} = w^{2} + (3 w + 9)^{2}

(x - 6)^{2} = 64

x^2+11/3 x-20/3 =0

x^{2} + \frac{11}{3} x - \frac{20}{3} = 0