What are the solutions to the equation 8a^2+6a=-5 ?

The solutions to the equation 8a^2+6a=-5 are a=-3/8+i(sqrt(31))/8 ,a=-3/8-i(sqrt(31))/8

Find the zeros of 8a^2+6a=-5

The zeros of 8a^2+6a=-5 are a=-3/8+i(sqrt(31))/8 ,a=-3/8-i(sqrt(31))/8

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8 a^{2} + 6 a = - 5

a = - \frac{3}{8} + i \frac{31}{8}, a = - \frac{3}{8} - i \frac{31}{8}

Solution steps

8 a^{2} + 6 a = - 5

Move

5

to the left side

8 a^{2} + 6 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

Simplify

6^{2} - 4 \cdot 8 \cdot 5 : 231 i

a_{1, 2} = \frac{- 6 \pm 2 31 i}{2 \cdot 8}

Separate the solutions

a_{1} = \frac{- 6 + 2 31 i}{2 \cdot 8}, a_{2} = \frac{- 6 - 2 31 i}{2 \cdot 8}

a = \frac{- 6 + 2 31 i}{2 \cdot 8} : - \frac{3}{8} + i \frac{31}{8}

a = \frac{- 6 - 2 31 i}{2 \cdot 8} : - \frac{3}{8} - i \frac{31}{8}

The solutions to the quadratic equation are:

a = - \frac{3}{8} + i \frac{31}{8}, a = - \frac{3}{8} - i \frac{31}{8}

x^{2} + (x - 7)^{2} = (x + 2)^{2}

- 32 t + 100 = 0

5 (4)^{2}

j + 7 > - 6

\frac{3 x}{4} + 2 = 4 x - 1

What are the solutions to the equation 8a^2+6a=-5 ?
The solutions to the equation 8a^2+6a=-5 are a=-3/8+i(sqrt(31))/8 ,a=-3/8-i(sqrt(31))/8
Find the zeros of 8a^2+6a=-5
The zeros of 8a^2+6a=-5 are a=-3/8+i(sqrt(31))/8 ,a=-3/8-i(sqrt(31))/8