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受欢迎的代数 >

a^2x+(a-1)=(a+1)x

解答

a^{2} x + (a - 1) = (a + 1) x

解答

x = \frac{- a + 1}{a ^{2} - a - 1}; a \neq = \frac{1 + 5}{2}, a \neq = \frac{1 - 5}{2}

求解步骤

a^{2} x + (a - 1) = (a + 1) x

a^{2} x + a - 1 = (a + 1) x

展开

(a + 1) x : a x + x

a^{2} x + a - 1 = a x + x

将

a

到右边

a^{2} x - 1 = a x + x - a

将

1

到右边

a^{2} x = a x + x - a + 1

两边减去

a x + x

a^{2} x - (a x + x) = a x + x - a + 1 - (a x + x)

化简

a^{2} x - a x - x = - a + 1

分解

a^{2} x - a x - x : x (a^{2} - a - 1)

x (a^{2} - a - 1) = - a + 1

两边除以

a^{2} - a - 1; a \neq = \frac{1 + 5}{2}, a \neq = \frac{1 - 5}{2}

x = \frac{- a + 1}{a ^{2} - a - 1}; a \neq = \frac{1 + 5}{2}, a \neq = \frac{1 - 5}{2}

作图

流行的例子

x - 14 = - 10

2 = 5 + v

- 2 - 5 k = 0

solvefor x,8x-4y=12

so l v e f or x, 8 x - 4 y = 12

10 = 7 - x