What is the answer to (3x-1)^2-3(2x+3)^2+42=2x(-x-5)-(x-1)^2 ?

The answer to (3x-1)^2-3(2x+3)^2+42=2x(-x-5)-(x-1)^2 is x= 1/2

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(3x-1)^2-3(2x+3)^2+42=2x(-x-5)-(x-1)^2

(3 x - 1)^{2} - 3 (2 x + 3)^{2} + 42 = 2 x (- x - 5) - (x - 1)^{2}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

(3 x - 1)^{2} - 3 (2 x + 3)^{2} + 42 = 2 x (- x - 5) - (x - 1)^{2}

Expand

(3 x - 1)^{2} - 3 (2 x + 3)^{2} + 42 : - 3 x^{2} - 42 x + 16

Expand

2 x (- x - 5) - (x - 1)^{2} : - 3 x^{2} - 8 x - 1

- 3 x^{2} - 42 x + 16 = - 3 x^{2} - 8 x - 1

Move

16

to the right side

- 3 x^{2} - 42 x = - 3 x^{2} - 8 x - 17

Subtract

- 3 x^{2} - 8 x

from both sides

- 3 x^{2} - 42 x - (- 3 x^{2} - 8 x) = - 3 x^{2} - 8 x - 17 - (- 3 x^{2} - 8 x)

Simplify

- 34 x = - 17

Divide both sides by

- 34

x = \frac{1}{2}

x, 15 x + 3 y = 27

b, m = \frac{b}{9 - 4 h ^{3}}

x, 12 x + 8 y = - 48

h, h + h (\frac{x - 1}{x}) = 2 x + 4

x, 5 x + 7 y = - 1

What is the answer to (3x-1)^2-3(2x+3)^2+42=2x(-x-5)-(x-1)^2 ?
The answer to (3x-1)^2-3(2x+3)^2+42=2x(-x-5)-(x-1)^2 is x= 1/2
Solve for x: (3x-1)^2-3(2x+3)^2+42=2x(-x-5)-(x-1)^2
The solution is x= 1/2