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受欢迎的代数 >

solvefor x,2xy^2-3=6y^2+x

解答

求解

x, 2 x y^{2} - 3 = 6 y^{2} + x

解答

x = \frac{6 y ^{2} + 3}{2 y ^{2} - 1}; y \neq = \frac{1}{2}, y \neq = - \frac{1}{2}

求解步骤

2 x y^{2} - 3 = 6 y^{2} + x

将

3

到右边

2 x y^{2} = 6 y^{2} + x + 3

将

x

para o lado esquerdo

2 x y^{2} - x = 6 y^{2} + 3

分解

2 x y^{2} - x : x (2 y^{2} - 1)

x (2 y^{2} - 1) = 6 y^{2} + 3

两边除以

2 y^{2} - 1; y \neq = \frac{1}{2}, y \neq = - \frac{1}{2}

x = \frac{6 y ^{2} + 3}{2 y ^{2} - 1}; y \neq = \frac{1}{2}, y \neq = - \frac{1}{2}

作图

流行的例子

solvefor x,2x=0

so l v e f or x, 2 x = 0

2 + 3 x = 8 - 3 (x + 2)

solvefor x,y+2= 1/2 (x+2)

so l v e f or x, y + 2 = \frac{1}{2} (x + 2)

-1/5 f+8= 3/5 (5/3 f+15)-(-1/5)f

- \frac{1}{5} f + 8 = \frac{3}{5} (\frac{5}{3} f + 15) - (- \frac{1}{5}) f

w - 8 = 12