zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor x,(k-3)x-(4-k^2)y+k^2-7k+6=0

解答

求解

x, (k - 3) x - (4 - k^{2}) y + k^{2} - 7 k + 6 = 0

解答

x = \frac{y ( - k ^{2} + 4 ) - k ^{2} + 7 k - 6}{k - 3}; k \neq = 3

求解步骤

(k - 3) x - (4 - k^{2}) y + k^{2} - 7 k + 6 = 0

将

(4 - k^{2}) y

到右边

(k - 3) x + k^{2} - 7 k + 6 = y (- k^{2} + 4)

将

k^{2}

到右边

(k - 3) x - 7 k + 6 = y (- k^{2} + 4) - k^{2}

将

7 k

到右边

(k - 3) x + 6 = y (- k^{2} + 4) - k^{2} + 7 k

将

6

到右边

(k - 3) x = y (- k^{2} + 4) - k^{2} + 7 k - 6

两边除以

k - 3; k \neq = 3

x = \frac{y ( - k ^{2} + 4 ) - k ^{2} + 7 k - 6}{k - 3}; k \neq = 3

作图

流行的例子

2/3 (2y-3)= 1/2 (4y+2)

\frac{2}{3} (2 y - 3) = \frac{1}{2} (4 y + 2)

5(x+5)=2x+26+2x

5 (x + 5) = 2 x + 26 + 2 x

9-4(3x+1)=3(6-3x)-9

9 - 4 (3 x + 1) = 3 (6 - 3 x) - 9

-(4m+2)+2m=16-6(2m+3)

- (4 m + 2) + 2 m = 16 - 6 (2 m + 3)

solvefor x,4x-y=14

so l v e f or x, 4 x - y = 14