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受欢迎的代数 >

x^2+6x+14=(x-h)^2+k

解答

x^{2} + 6 x + 14 = (x - h)^{2} + k

解答

x = \frac{h ^{2} + k - 14}{2 ( 3 + h )}; h \neq = - 3

求解步骤

x^{2} + 6 x + 14 = (x - h)^{2} + k

展开

(x - h)^{2} + k : x^{2} - 2 h x + h^{2} + k

x^{2} + 6 x + 14 = x^{2} - 2 h x + h^{2} + k

将

14

到右边

x^{2} + 6 x = x^{2} - 2 h x + h^{2} + k - 14

两边减去

x^{2} - 2 h x

x^{2} + 6 x - (x^{2} - 2 h x) = x^{2} - 2 h x + h^{2} + k - 14 - (x^{2} - 2 h x)

化简

2 h x + 6 x = h^{2} + k - 14

分解

2 h x + 6 x : 2 x (h + 3)

2 x (h + 3) = h^{2} + k - 14

两边除以

2 (h + 3); h \neq = - 3

x = \frac{h ^{2} + k - 14}{2 ( 3 + h )}; h \neq = - 3

作图

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