Xω=(8(1+jω))/(9-6jω+ω^2)

解答

X ω = \frac{8 ( 1 + jω )}{9 - 6 jω + ω ^{2}}

X = \frac{8 ( 1 + ωj )}{ω ( 9 - 6 ωj + ω ^{2} )}; ω \neq = 0

求解步骤

X ω = \frac{8 ( 1 + jω )}{9 - 6 jω + ω ^{2}}

两边除以

ω; ω \neq = 0

X = \frac{8 ( 1 + ωj )}{ω ( 9 - 6 ωj + ω ^{2} )}; ω \neq = 0

E = 5 \frac{2}{3} - \frac{2}{1}

3 x + 4 = 3 x + 4

\frac{3 x}{5} - \frac{8}{3} = 7

- 9 = 5 m + 4 - 3

so l v e f or L, S = L - R L