vereinfachen ((-8x^3)/(y^{-6)})^{2/3}

Lösung

vereinfachen

(\frac{- 8 x ^{3}}{y ^{- 6}})^{\frac{2}{3}}

4 x^{2} y^{4}

Schritte zur Lösung

(\frac{- 8 x ^{3}}{y ^{- 6}})^{\frac{2}{3}}

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( - 8 x ^{3} ) ^{\frac{2}{3}}}{( y ^{- 6} ) ^{\frac{2}{3}}}

Vereinfache

(y^{- 6})^{\frac{2}{3}} : \frac{1}{y ^{4}}

= \frac{( - 8 x ^{3} ) ^{\frac{2}{3}}}{\frac{1}{y ^{4}}}

(- 8 x^{3})^{\frac{2}{3}} = (8 x^{3})^{\frac{2}{3}}

= \frac{( 8 x ^{3} ) ^{\frac{2}{3}}}{\frac{1}{y ^{4}}}

Wende Bruchregel an:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( 8 x ^{3} ) ^{\frac{2}{3}} y ^{4}}{1}

Wende Regel an

\frac{a}{1} = a

= y^{4} (8 x^{3})^{\frac{2}{3}}

(8 x^{3})^{\frac{2}{3}} = 4 x^{2}

= 4 x^{2} y^{4}

(x - 5)^{2} = 1

- 3 \leq x \leq 2

f a c t or 8 x^{7} - 27 x^{4}

0 = 4 z + 8 z^{2}

\frac{x - 10}{x + 5} \geq 0