What is ((4x^2yz^3)^2)/(2x^3y^2z^{-4)} ?

The solution to ((4x^2yz^3)^2)/(2x^3y^2z^{-4)} is 8xz^{10}

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simplify ((4x^2yz^3)^2)/(2x^3y^2z^{-4)}

simplify

\frac{( 4 x ^{2} y z ^{3} ) ^{2}}{2 x ^{3} y ^{2} z ^{- 4}}

8 x z^{10}

Solution steps

\frac{( 4 x ^{2} y z ^{3} ) ^{2}}{2 x ^{3} y ^{2} z ^{- 4}}

Simplify

(4 x^{2} y z^{3})^{2} : 16 x^{4} y^{2} z^{6}

= \frac{16 x ^{4} y ^{2} z ^{6}}{2 x ^{3} y ^{2} z ^{- 4}}

Cancel the common factor:

y^{2}

= \frac{16 x ^{4} z ^{6}}{2 x ^{3} z ^{- 4}}

Factor the number:

16 = 2 \cdot 8

= \frac{2 \cdot 8 x ^{4} z ^{6}}{2 x ^{3} z ^{- 4}}

Cancel the common factor:

2

= \frac{8 x ^{4} z ^{6}}{x ^{3} z ^{- 4}}

Simplify

\frac{x ^{4}}{x ^{3}} : x

= \frac{8 x z ^{6}}{z ^{- 4}}

Simplify

\frac{z ^{6}}{z ^{- 4}} : z^{10}

= 8 x z^{10}

1^{2} + 1^{2} + 1^{2}

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(4 + 6 i) - (8 + 3 i)

3 \cdot (- 9)

(2 x + 5) (3 - 4 x)

What is ((4x^2yz^3)^2)/(2x^3y^2z^{-4)} ?
The solution to ((4x^2yz^3)^2)/(2x^3y^2z^{-4)} is 8xz^{10}