因式分解 5x^3+40y^6

解答

因式分解

5 x^{3} + 40 y^{6}

5 (x + 2 y^{2}) (x^{2} - 2 x y^{2} + 4 y^{4})

求解步骤

5 x^{3} + 40 y^{6}

因式分解出通项

5 : 5 (x^{3} + 8 y^{6})

= 5 (x^{3} + 8 y^{6})

因式分解

x^{3} + 8 y^{6} : (x + 2 y^{2}) (x^{2} - 2 x y^{2} + 4 y^{4})

= 5 (x + 2 y^{2}) (x^{2} - 2 x y^{2} + 4 y^{4})

s im pl i f y (- 4) \cdot (- 3)

s im pl i f y (\frac{- 2 x ^{6} y}{3 z ^{5}})^{3}

s im pl i f y \frac{x - 9}{x ^{2} - 9} + \frac{x + 9}{x ^{2} + 3 x} + \frac{x + 3}{x ^{2} - 3 x}

f a c t or 15 x^{3} y^{2} + 10 x^{2} y^{3} - 15 x^{2} y^{2} z

e x p an d (2 x + 2) (x - 1)