erweitern ((2x-3)^2)/3

Lösung

erweitern

\frac{( 2 x - 3 ) ^{2}}{3}

\frac{4 x ^{2}}{3} - 4 x + 3

Schritte zur Lösung

\frac{( 2 x - 3 ) ^{2}}{3}

(2 x - 3)^{2} = 4 x^{2} - 12 x + 9

= \frac{4 x ^{2} - 12 x + 9}{3}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 12 x + 9}{3} = \frac{4 x ^{2}}{3} - \frac{12 x}{3} + \frac{9}{3}

= \frac{4 x ^{2}}{3} - \frac{12 x}{3} + \frac{9}{3}

Teile die Zahlen:

\frac{12}{3} = 4

= \frac{4 x ^{2}}{3} - 4 x + \frac{9}{3}

Teile die Zahlen:

\frac{9}{3} = 3

= \frac{4 x ^{2}}{3} - 4 x + 3

e x p an d \frac{1}{2} (2 - ln (2 + 1))

e x p an d (2 q + r)^{\frac{2}{3}}

e x p an d 2 sin (\frac{π}{3} (x - 4)) + 6

e x p an d \frac{d}{d x} ((x - π) e^{x - π}) + sin (x)

e x p an d (5 e^{3} + 3 f^{2})^{6}