展开 x^2+i^3x+i^2

解答

展开

x^{2} + i^{3} x + i^{2}

(x^{2} - 1) - i x

求解步骤

x^{2} + i^{3} x + i^{2}

i^{3} = - i

= x^{2} - i x + i^{2}

使用虚数运算法则:

i^{2} = - 1

= x^{2} - i x - 1

将

x^{2} - i x - 1

改写成标准复数形式:

(x^{2} - 1) - x i

= (x^{2} - 1) - x i

e x p an d \frac{10}{( x + 1 ) ^{3}}

e x p an d l [(1 + e^{2 t})^{2}]

e x p an d d x (cos (x) + sin (x))

e x p an d \frac{2 ( 1 - ln ( x ) )}{x ^{2}}

e x p an d \frac{4 π ( 20 10 - 10 5 )}{3}