展开 [(sin(x)+7cos(x)-1)dx]

解答

展开

[(sin (x) + 7 cos (x) - 1) d x]

sin (x) d x + 7 cos (x) d x - d x

求解步骤

(sin (x) + 7 cos (x) - 1) d x

打开括号

= d x sin (x) + d x \cdot 7 cos (x) + d x (- 1)

使用加减运算法则

+ (- a) = - a

= sin (x) d x + 7 cos (x) d x - 1 \cdot d x

乘以:

1 \cdot d x = d x

= sin (x) d x + 7 cos (x) d x - d x

e x p an d e^{t} (t + 3)

e x p an d (2 y - x) d y

s im pl i f y \frac{245.42}{( s + 10 ) ( s ^{2} + 4 s + 24.542 )}

e x p an d (\frac{1}{4} + \frac{3}{4} e^{t})^{5}

e x p an d \frac{1}{s ^{3} ( s ^{2} - 1 )}