展开 (100)/((2182j+1)(2182j+10)^2)

解答

展开

\frac{100}{( 2182 j + 1 ) ( 2182 j + 10 ) ^{2}}

\frac{25}{2597193142 j ^{3} + 24995901 j ^{2} + 65460 j + 25}

求解步骤

\frac{100}{( 2182 j + 1 ) ( 2182 j + 10 ) ^{2}}

(2182 j + 10)^{2} = 4761124 j^{2} + 43640 j + 100

= \frac{100}{( 2182 j + 1 ) ( 4761124 j ^{2} + 43640 j + 100 )}

分解

4761124 j^{2} + 43640 j + 100 : 4 (1190281 j^{2} + 10910 j + 25)

= \frac{100}{( 2182 j + 1 ) \cdot 4 ( 1190281 j ^{2} + 10910 j + 25 )}

数字相除:

\frac{100}{4} = 25

= \frac{25}{( 2182 j + 1 ) ( 1190281 j ^{2} + 10910 j + 25 )}

乘开

(2182 j + 1) (1190281 j^{2} + 10910 j + 25) : 2597193142 j^{3} + 24995901 j^{2} + 65460 j + 25

= \frac{25}{2597193142 j ^{3} + 24995901 j ^{2} + 65460 j + 25}

s im pl i f y \frac{6.3223 ( s + 1.4235 ) ^{2}}{s} + \frac{1}{s ( s + l ) ( s + 5 )}

e x p an d (e^{t} cos (t) - e^{t} sin (t) + e^{t})^{2}

e x p an d 4 (1 + e^{2})

e x p an d 2 y d x + (x - sin (y^{\frac{1}{2}})) d y

e x p an d (a^{4}) 3