解答
展开 2k11+2k4(k14+4k7+3)
解答
2k3−2373+273⋅372+2k374−2k73⋅373−2k2375+2k273⋅374+2k3376−2k373⋅375+2k473⋅376
求解步骤
2k11+2k4k14+4k7+3
分解 k14+4k7+3:(k+1)(k+73)(k6−k5+k4−k3+k2−k+1)(k6−73k5+372k4−373k3+374k2−375k+376)
=2k11+2k4(k+1)(k+73)(k6−k5+k4−k3+k2−k+1)(k6−73k5+372k4−373k3+374k2−375k+376)
分解 2k11+2k4:2k4(k+1)(k6−k5+k4−k3+k2−k+1)
=2k4(k+1)(k6−k5+k4−k3+k2−k+1)(k+1)(k+73)(k6−k5+k4−k3+k2−k+1)(k6−73k5+372k4−373k3+374k2−375k+376)
消掉 2k4(k+1)(k6−k5+k4−k3+k2−k+1)(k+1)(k+73)(k6−k5+k4−k3+k2−k+1)(k6−73k5+372k4−373k3+374k2−375k+376):2k4(k+73)(k6−73k5+372k4−373k3+374k2−375k+376)
=2k4(k+73)(k6−73k5+372k4−373k3+374k2−375k+376)
乘开 (k+73)(k6−73k5+372k4−373k3+374k2−375k+376):k7−373k4+73⋅372k4+374k3−73⋅373k3−375k2+73⋅374k2+376k−73⋅375k+73⋅376
=2k4k7−373k4+73⋅372k4+374k3−73⋅373k3−375k2+73⋅374k2+376k−73⋅375k+73⋅376
使用分式法则: ca±b=ca±cb2k4k7−373k4+73⋅372k4+374k3−73⋅373k3−375k2+73⋅374k2+376k−73⋅375k+73⋅376=2k4k7−2k4373k4+2k473⋅372k4+2k4374k3−2k473⋅373k3−2k4375k2+2k473⋅374k2+2k4376k−2k473⋅375k+2k473⋅376=2k4k7−2k4373k4+2k473⋅372k4+2k4374k3−2k473⋅373k3−2k4375k2+2k473⋅374k2+2k4376k−2k473⋅375k+2k473⋅376
2k4k7=2k3
2k4373k4=2373
2k473⋅372k4=273⋅372
2k4374k3=2k374
2k473⋅373k3=2k73⋅373
2k4375k2=2k2375
2k473⋅374k2=2k273⋅374
2k4376k=2k3376
2k473⋅375k=2k373⋅375
=2k3−2373+273⋅372+2k374−2k73⋅373−2k2375+2k273⋅374+2k3376−2k373⋅375+2k473⋅376
流行的例子
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