erweitern ((x+2)(2x-1))/2

Lösung

erweitern

\frac{( x + 2 ) ( 2 x - 1 )}{2}

x^{2} + \frac{3 x}{2} - 1

Schritte zur Lösung

\frac{( x + 2 ) ( 2 x - 1 )}{2}

Multipliziere aus

(x + 2) (2 x - 1) : 2 x^{2} + 3 x - 2

= \frac{2 x ^{2} + 3 x - 2}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 3 x - 2}{2} = \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{2}{2}

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - \frac{2}{2}

Wende Regel an

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{2 x ^{2}}{2} + \frac{3 x}{2} - 1

Teile die Zahlen:

\frac{2}{2} = 1

= x^{2} + \frac{3 x}{2} - 1

e x p an d (r + e)^{3} + (r + e)^{2}

e x p an d \frac{p ( x )}{( x - 1 ) ( x + 1 ) ( x - 2 ) ( x + 2 )}

e x p an d \frac{4}{s ^{2} ( s + 2 )}

e x p an d \frac{1}{p ( 1 - p )}

e x p an d 2 (2 e^{- x} x - e^{- x} x^{2})