erweitern (4(3x^2-1))/((x^2+1)^3)

Lösung

erweitern

\frac{4 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

\frac{12 x ^{2} - 4}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

Schritte zur Lösung

\frac{4 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

(x^{2} + 1)^{3} = x^{6} + 3 x^{4} + 3 x^{2} + 1

= \frac{4 ( 3 x ^{2} - 1 )}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

Multipliziere aus

4 (3 x^{2} - 1) : 12 x^{2} - 4

= \frac{12 x ^{2} - 4}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

e x p an d (1 + ab f) {1 + (c + d) e h} e - (ab e (c + d) g)

e x p an d A (3, 4) B (8, - 6)

e x p an d \frac{x}{( x ^{2} + 1 ) ( x ^{2} + 2 x + 3 )}

e x p an d \frac{x ^{7} + 2}{( x ^{2} + x + 1 ) ^{2}}

e x p an d \frac{2 ^{n}}{( 2 ^{n + 1} - 1 ) ( 2 ^{n} - 1 )}