展开 (2k)/(((2jw+1)(jw+1)(jw+2)))

解答

展开

\frac{2 k}{( ( 2 j w + 1 ) ( j w + 1 ) ( j w + 2 ) )}

\frac{2 k}{2 j ^{3} w ^{3} + 7 j ^{2} w ^{2} + 7 j w + 2}

求解步骤

\frac{2 k}{( 2 j w + 1 ) ( j w + 1 ) ( j w + 2 )}

乘开

(2 j w + 1) (j w + 1) (j w + 2) : 2 j^{3} w^{3} + 7 j^{2} w^{2} + 7 j w + 2

= \frac{2 k}{2 j ^{3} w ^{3} + 7 j ^{2} w ^{2} + 7 j w + 2}

e x p an d \frac{6 x ^{2}}{( x - 1 ) ^{4}}

e x p an d \frac{( x - 1 ) ( 3 x ^{2} + 3 x + 2 )}{( x + 1 )}

e x p an d \frac{x ^{3} - 4 x ^{2} + 5 x + 1}{x ( x - 1 ) ^{2}}

e x p an d \frac{ln ( n + 1 )}{( n + 1 ) ^{3}}

e x p an d \frac{( 131 x - 25 )}{( ( x - 11 ) ( x + 13 ) )}