展开-(Be^{Bx})/((1+e^{Bx))^2}

解答

展开

- \frac{B e ^{B x}}{( 1 + e ^{B x} ) ^{2}}

- \frac{B e ^{B x}}{1 + 2 e ^{B x} + e ^{2 B x}}

求解步骤

- \frac{B e ^{B x}}{( 1 + e ^{B x} ) ^{2}}

(1 + e^{B x})^{2} = 1 + 2 e^{B x} + e^{2 B x}

= - \frac{B e ^{B x}}{2 e ^{B x} + e ^{2 B x} + 1}

e x p an d (3 + 2 x - x^{2})^{5}

e x p an d 4 (1 - e^{- 0.13 t})

e x p an d \frac{5 x ^{2} - 8 x + 1}{( x + 1 ) ( x - 3 )}

e x p an d \frac{x ( 3 x - 2 ) ( x - 2 )}{2 ( 3 x - 5 )}

e x p an d (x + 1) (- e^{- x})