erweitern ((8+x)(x^2+1))/2

Lösung

erweitern

\frac{( 8 + x ) ( x ^{2} + 1 )}{2}

\frac{x ^{3}}{2} + 4 x^{2} + \frac{x}{2} + 4

Schritte zur Lösung

\frac{( 8 + x ) ( x ^{2} + 1 )}{2}

Multipliziere aus

(8 + x) (x^{2} + 1) : 8 x^{2} + 8 + x^{3} + x

= \frac{8 x ^{2} + 8 + x ^{3} + x}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 x ^{2} + 8 + x ^{3} + x}{2} = \frac{8 x ^{2}}{2} + \frac{8}{2} + \frac{x ^{3}}{2} + \frac{x}{2}

= \frac{8 x ^{2}}{2} + \frac{8}{2} + \frac{x ^{3}}{2} + \frac{x}{2}

Teile die Zahlen:

\frac{8}{2} = 4

= 4 x^{2} + 4 + \frac{x ^{3}}{2} + \frac{x}{2}

Rewrite in standard form

= \frac{x ^{3}}{2} + 4 x^{2} + \frac{x}{2} + 4

e x p an d (x - 2 + 2)^{2} (x - 2 - 2)^{2}

\frac{d}{d y} ((x (y)) (y^{2} + 1))

e x p an d \frac{1}{( x - 1 ) ( x - 4 )}

e x p an d (x - 3) e^{∣ x + 1 ∣}

e x p an d (t - 2) cos (3 t) e^{2 t}