展开 (m_{1}*m_{2})x''+k(x-l)(m_{1}-m_{2})

解答

展开

(m_{1} \cdot m_{2}) x^{''} + k (x - l) (m_{1} - m_{2})

m_{1} m_{2} x'' + m_{1} k x - m_{2} k x - m_{1} l k + m_{2} l k

求解步骤

(m_{1} m_{2}) x^{''} + k (x - l) (m_{1} - m_{2})

乘开

k (x - l) (m_{1} - m_{2}) : m_{1} k x - m_{2} k x - m_{1} l k + m_{2} l k

= (m_{1} m_{2}) x^{''} + m_{1} k x - m_{2} k x - m_{1} l k + m_{2} l k

去除括号:

(a) = a

= m_{1} m_{2} x^{^{''}} + m_{1} k x - m_{2} k x - m_{1} l k + m_{2} l k

e x p an d \frac{( 5 + i ) ^{4}}{( 4 - 3 i ) ^{4}}

e x p an d (A x + B) e^{x}

e x p an d π (2 - 1) - 2

e x p an d, (2 x + 1) (4 x + 3)

e x p an d A (1 - e^{\frac{t}{d}})