erweitern ((2x-8)^2)/9

Lösung

erweitern

\frac{( 2 x - 8 ) ^{2}}{9}

\frac{4 x ^{2}}{9} - \frac{32 x}{9} + \frac{64}{9}

Schritte zur Lösung

\frac{( 2 x - 8 ) ^{2}}{9}

(2 x - 8)^{2} = 4 x^{2} - 32 x + 64

= \frac{4 x ^{2} - 32 x + 64}{9}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 32 x + 64}{9} = \frac{4 x ^{2}}{9} - \frac{32 x}{9} + \frac{64}{9}

= \frac{4 x ^{2}}{9} - \frac{32 x}{9} + \frac{64}{9}

e x p an d \frac{1}{2} + (x - \frac{1}{2}) e^{x}

e x p an d \frac{1 + 3 x}{( 1 + 2 x )}

e x p an d \frac{1}{2} p o w (x, 4) - p o w (x + 1, 3) - 3 p o w (x, 2)

e x p an d \frac{1}{2} (\frac{a ^{2} - 1}{2} + \frac{1}{2} (e^{- 2 a} - \frac{1}{e ^{2}}))

e x p an d \frac{1}{3} (- 3)^{3} + \frac{1}{2} (- 3)^{2} - 2 (- 3)