erweitern ((8+x)(x^2+x-2))/2

Lösung

erweitern

\frac{( 8 + x ) ( x ^{2} + x - 2 )}{2}

\frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + 3 x - 8

Schritte zur Lösung

\frac{( 8 + x ) ( x ^{2} + x - 2 )}{2}

Multipliziere aus

(8 + x) (x^{2} + x - 2) : x^{3} + 9 x^{2} + 6 x - 16

= \frac{x ^{3} + 9 x ^{2} + 6 x - 16}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 9 x ^{2} + 6 x - 16}{2} = \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{6 x}{2} - \frac{16}{2}

= \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{6 x}{2} - \frac{16}{2}

Teile die Zahlen:

\frac{6}{2} = 3

= \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + 3 x - \frac{16}{2}

Teile die Zahlen:

\frac{16}{2} = 8

= \frac{x ^{3}}{2} + \frac{9 x ^{2}}{2} + 3 x - 8

e x p an d \frac{x + 1 - x ^{2}}{2 x - ( x + 1 ) ( x - 1 )}

e x p an d \frac{( 1 )}{( x ( x + 1 ) )}

e x p an d 1 - e^{10 k - 10 (a_{0} + 0.00512)}

e x p an d e^{2 x} (x - 1) + (x - 1) e^{x}

e x p an d 20 (4 x^{3} - 3 x)^{19} (12 x^{2} - 3)