展开 ((6x^2+3x))/((x^2+1)(x^2+4))

解答

展开

\frac{( 6 x ^{2} + 3 x )}{( x ^{2} + 1 ) ( x ^{2} + 4 )}

\frac{6 x ^{2} + 3 x}{x ^{4} + 5 x ^{2} + 4}

求解步骤

\frac{6 x ^{2} + 3 x}{( x ^{2} + 1 ) ( x ^{2} + 4 )}

乘开

(x^{2} + 1) (x^{2} + 4) : x^{4} + 5 x^{2} + 4

= \frac{6 x ^{2} + 3 x}{x ^{4} + 5 x ^{2} + 4}

e x p an d \frac{8 x - 3}{( x + 3 ) ( x - 3 ) ( 2 x - 3 ) ( x ^{2} - x - 6 )}

e x p an d x^{3 (n + 1)}

e x p an d \frac{24}{( s + 2 ) ^{5}}

e x p an d W (sin (6 0^{\circ}) + 0.22 cos (6 0^{\circ}) = 55.2754)

e x p an d \frac{( s + 8 ) ( s + 55.92 )}{( s + 3 ) ( s + 6 ) ( s + 10 )}