erweitern ((2x+1)^2)/(16)

Lösung

erweitern

\frac{( 2 x + 1 ) ^{2}}{16}

\frac{x ^{2}}{4} + \frac{x}{4} + \frac{1}{16}

Schritte zur Lösung

\frac{( 2 x + 1 ) ^{2}}{16}

(2 x + 1)^{2} = 4 x^{2} + 4 x + 1

= \frac{4 x ^{2} + 4 x + 1}{16}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} + 4 x + 1}{16} = \frac{4 x ^{2}}{16} + \frac{4 x}{16} + \frac{1}{16}

= \frac{4 x ^{2}}{16} + \frac{4 x}{16} + \frac{1}{16}

Streiche

\frac{4 x ^{2}}{16} : \frac{x ^{2}}{4}

= \frac{x ^{2}}{4} + \frac{4 x}{16} + \frac{1}{16}

Streiche

\frac{4 x}{16} : \frac{x}{4}

= \frac{x ^{2}}{4} + \frac{x}{4} + \frac{1}{16}

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e x p an d \frac{sin ^{2} ( x )}{( cos ( x ) + 1 ) ^{2}}

e x p an d sin (x (π - \frac{π}{k}))