vereinfachen-(9/13 log_{2}(9/13)+4/13 log_{2}(4/13))

Lösung

vereinfachen

- (\frac{9}{13} lo g_{2} (\frac{9}{13}) + \frac{4}{13} lo g_{2} (\frac{4}{13}))

- \frac{lo g _{2} ( \frac{99179645184}{1 3 ^{9} \cdot 28561} )}{13}

Dezimale

0.89049 \dots

Schritte zur Lösung

- (\frac{9}{13} lo g_{2} (\frac{9}{13}) + \frac{4}{13} lo g_{2} (\frac{4}{13}))

\frac{9}{13} lo g_{2} (\frac{9}{13}) + \frac{4}{13} lo g_{2} (\frac{4}{13}) = \frac{9 lo g _{2} ( \frac{9}{13} ) + 4 lo g _{2} ( \frac{4}{13} )}{13}

= - \frac{9 lo g _{2} ( \frac{9}{13} ) + 4 lo g _{2} ( \frac{4}{13} )}{13}

9 lo g_{2} (\frac{9}{13}) + 4 lo g_{2} (\frac{4}{13}) = lo g_{2} (\frac{99179645184}{1 3 ^{9} \cdot 28561})

= - \frac{lo g _{2} ( \frac{99179645184}{1 3 ^{9} \cdot 28561} )}{13}

e x p an d ln (20) (e^{\frac{x}{52}} - 1)

e x p an d 2 t^{4} e^{- 2 t} + [U^{4} (t) (t - 3)]

e x p an d sin ((4 n + 3) \cdot 9 0^{\circ})

e x p an d \frac{2 x}{( x - 2 ) ( x + 1 )}

e x p an d (A + B = 1,) - (- 2 A + B = - 1)