erweitern 1/2 (sqrt(2)+ln(1+sqrt(2)))

Lösung

erweitern

\frac{1}{2} (2 + ln (1 + 2))

\frac{1}{2} + \frac{ln ( 1 + 2 )}{2}

Dezimale

1.14779 \dots

Schritte zur Lösung

\frac{1}{2} (2 + ln (1 + 2))

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = \frac{1}{2}, b = 2, c = ln (1 + 2)

= \frac{1}{2} 2 + \frac{1}{2} ln (1 + 2)

= 2 \frac{1}{2} + \frac{1}{2} ln (1 + 2)

Vereinfache

2 \frac{1}{2} + \frac{1}{2} ln (1 + 2) : \frac{1}{2} + \frac{ln ( 1 + 2 )}{2}

= \frac{1}{2} + \frac{ln ( 1 + 2 )}{2}

e x p an d \frac{( x ^{2} + 1 ) ( x ^{2} - 2 )}{x ^{\frac{2}{3}}}

e x p an d \frac{x - 4}{3 x ^{2}}

e x p an d \frac{- 1 + 4 a}{3 ( - 1 + a )}

e x p an d 1 + x^{- 2}

e x p an d - \frac{x ( x + 2 )}{( x + 1 ) ^{2}}