展開する product(3x+2)(4x^2-7x+1)is

解

展開する

p ro d u c t (3 x + 2) (4 x^{2} - 7 x + 1) i s

12 c i p ro t x^{3} s d u - 13 c i p ro t x^{2} s d u - 11 c i p ro t x s d u + 2 c i p ro t s d u

解答ステップ

p ro d u c t (3 x + 2) (4 x^{2} - 7 x + 1) i s

= c i p ro t s d u (3 x + 2) (4 x^{2} - 7 x + 1)

拡張

(3 x + 2) (4 x^{2} - 7 x + 1) : 12 x^{3} - 13 x^{2} - 11 x + 2

= p ro d u c t i s (12 x^{3} - 13 x^{2} - 11 x + 2)

拡張

p ro d u c t i s (12 x^{3} - 13 x^{2} - 11 x + 2) : 12 c i p ro t x^{3} s d u - 13 c i p ro t x^{2} s d u - 11 c i p ro t x s d u + 2 c i p ro t s d u

= 12 c i p ro t x^{3} s d u - 13 c i p ro t x^{2} s d u - 11 c i p ro t x s d u + 2 c i p ro t s d u